Euler Problem 2

Each new term in the Fibonacci sequence is generated by adding the previous two terms. By starting with 1 and 2, the first 10 terms will be:

1, 2, 3, 5, 8, 13, 21, 34, 55, 89, …

Find the sum of all the even-valued terms in the sequence which do not exceed four million.

By definition, aren’t the first two Fibonacci numbers 0 and 1? Each next number is the sum of the previous two, blah blah blah. Guess we’ll have to provide code to trim the leading 0 and 1.

public class Euler2
{
    public static void main(String[] args)
    {
        Euler2 e = new Euler2();
        System.out.print(“Problem 2:\nSum of Even = ” + e.Problem2()+ “\n”);
    }

    public String Problem2 ()
    {
        int a=0;
        int b=1;
        int step = 1;
        int sum = 0;
        while (a < 4000000)
        {
            if (step > 2)
            {
                if (a % 2 == 0)
                {
                    sum += a;
                }
            }
            a=a+b;
            b=a-b;
            step++;
        }
        return String.valueOf(sum);
    }
}

 

Leave a Reply

Fill in your details below or click an icon to log in:

WordPress.com Logo

You are commenting using your WordPress.com account. Log Out /  Change )

Twitter picture

You are commenting using your Twitter account. Log Out /  Change )

Facebook photo

You are commenting using your Facebook account. Log Out /  Change )

Connecting to %s